14x^2+6x+2x=0

Solution for 14x^2+6x+2x=0 equation:

14x^2+6x+2x=0

We add all the numbers together, and all the variables

14x^2+8x=0

a = 14; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·14·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*14}=\frac{-16}{28}
=-4/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*14}=\frac{0}{28}
=0
$